Need help with solving right triangles again, can you guys solve for x too
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Answer:
Step-by-step explanation:
[tex]sin\theta =\frac{5}{13}\\ \\ \theta =sin^{-1}\frac{5}{13}\\ \\ \theta =22.62^o\\ \\ \\ a=90-22.62\\ \\ a=67.38^o\\ \\ \\ 13^2=5^2+x^2\\ \\ x^2=169-25\\ \\ x^2=144\\ \\ x=\sqrt{144}\\ \\ x=12[/tex]