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A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break , also the track can be stoped in 7.6 m\s if the driver hit the wall

Respuesta :

abidemiokin

Answer:

-4,651.42N

Explanation:

Since we are not asked what to find, we can calculate the force applied by the track as shown;

F = ma

F = m(v-u)/t

Substitute the given value

F = 4400(7.6-52)/42

F = 4400(-44.4)/42

F = -4,651.43N

Hence the required force is -4,651.42N

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