Respuesta :

drpelezo

Answer:

ΔG° = 80 Kj/mole

Explanation:

ΔG° = -R·T·ln(Kw)

R = 0.008314 Kj/mol·K

T = 25°C = 298K

Kw = 1 x 10⁻¹⁴

ΔG° = -R·T·ln(Kw) -(0.08314Kj/mol·K)(298K)ln(1 x 10⁻¹⁴)

= -(0.008314)(298)(-32.2)Kj/mole

= 79.78Kj/mole ≈ 80Kj/mole (1 sig.-fig.)

pstnonsonjoku

The change in free energy for the autoionization of water at 25°C is -79.9 KJ

Using the formula;

ΔG = -RTlnK

ΔG  = change in free energy = ?

R = gas constant = 8.314 J/K/mol

T = temperature = 298 K

K = equilibrium constant = 1.0 X 10^-14

Substituting into the given formula as;

ΔG = -  (8.314 J/K/mol × 298 K × ln(1.0 X 10^-14))

ΔG = -7.99 × 10^4 J/mol or -79.9 KJ/mol

Learn more: https://brainly.com/question/10038290

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