Answer:
d = 447.21 m, θ = 153.4º
Explanation:
Let's use the Pythagoras network theorem to find the magnitude of the displacement
d = [tex]\sqrt{x^2 + y^2}[/tex]
d = [tex]\sqrt{ 400^2 + 200^2}[/tex]
d = 447.21 m
To encode the direction, let's use trigonometry, we take the East and North directions as positive.
tan θ’= y / x
θ'= tan⁻¹ y / x
θ'= tan⁻¹ (200/400)
θ ’= 26.6º
This angle is in the second quadrant, so measured from the positive side of the x-axis (East direction)
θ = 180 - θ'
θ = 180 -26.6
θ = 153.4º
