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Can someone help me please

A 70.0 g piece of metal wire is heated, and the temperature of the wire changes from 58.0°C to 152.0°C. The amount of heat absorbed is 972 Joules. What is the specific heat of the metal wire?

a 0.148 J/gC
b 6.77 J/gC
c 724 J/gC
d 0.0913 J/gC

Can someone help me please A 700 g piece of metal wire is heated and the temperature of the wire changes from 580C to 1520C The amount of heat absorbed is 972 J class=

Respuesta :

leena

Hi there!

[tex]\large\boxed{\text{A. 0.148J/gC}}[/tex]

the equation q = mcΔT, where:

q = Energy (J)

cΔ = temperature change

m = mass of object

T = specific heat

Rearrange the equation to solve for the specific heat:

q/mcΔ = T

Plug in the given energy, mass, and temperature change to solve:

972 / (70 · (152 - 58)) = T

Simplify and solve:

972 / (70 · 94) = T

T = 972 / 6580 = 0.148 J/gC.

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