Answer:
0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Probability that a sophomore non-Chemistry major
Out of 92 students, 9 are non-chemistry major sophomores. So
[tex]P(A) = \frac{9}{92}[/tex]
Then a junior non-Chemistry major are chosen at random.
Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So
[tex]P(B) = \frac{10}{91}[/tex]
What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random
[tex]P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108[/tex]
0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.
