The following details is missing from the question.
A machining process produces screws for which the population proportion of screws with defective threads is 0.10 (10%)...
Answer:
[tex]H_a:\mu > 0.90[/tex]
Step-by-step explanation:
Given
[tex]n = 900[/tex]
[tex]Proportion= 0.10[/tex]
[tex]New\ Proportion = More\ than\ 0.90[/tex]
Required
Determine the alternate hypothesis
The initial given proportion represents the null hypothesis
i.e.
[tex]H_o:\mu = 0.10[/tex]
From the question, the new proportion is expected to pass the inspection with more than 0.90
More than, in inequalities means greater than.
So, the alternate hypothesis is:
[tex]H_a:\mu > 0.90[/tex]
