Answer:
d. Phosphoenolpyruvate + ADP + H+ --> pyruvate + ATP ∆G = -16.7 kJ/mol.
Explanation:
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In this case, since spontaneous reactions are characterized by a negative change in the Gibbs free energy of reaction (ΔG<0), we can notice that a, b and c are ruled out because a is at equilibrium (ΔG=0), both b and c are nonspontaneous (ΔG>0); therefore the spontaneous process is:
d. Phosphoenolpyruvate + ADP + H+ --> pyruvate + ATP ∆G = -16.7 kJ/mol
As this ΔG is negative (less than 0).
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