Respuesta :
Answer:
569K
Explanation:
Q = 3.5kJ = 3500J
mass = 28.2g
∅1 = 20°C = 20 + 273 = 293K
∅2 = x
c = 0.449
Q = mc∆∅
3500 = 28.2×0.449×∆∅
3500 = 12.6618×∆∅
∆∅ = 3500/12.6618
∆∅ = 276.4220
∅2 - ∅1 = 276.4220
∅2 = 276.4220 + ∅1
∅2 = 276.4220 + 293
∅2 = 569.4220K
∅2 = 569K
When the temperature is increased, there is the increase in thermal energy of the system. The final temperature of the iron in kelvins is 570 K.
What is energy?
The energy is the ability to do work.
Given is the energy Q = 3.5 kJ = 3500 J, mass of sample m = 28.2 g, specific heat of iron Cp = 0.449 J(g•K).
The initial temperature in kelvins is T1 = 20°C = 20 + 273 = 293K
The heat is related to the temperature difference as
Q = m c ∆T
Substitute the values into the expression,
3500 = 28.2 × 0.449 × ∆T
3500 = 12.6618 × (T2 -T1)
T2 - T1 = 276.4220
T2 = 276.4220 K +293 K
T2 = 569.4220K
The temperature of the iron is approximately 570 K.
Thus, the final temperature of the iron in kelvins is 570K.
Learn more about energy.
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