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At a teddy bear workshop, customers can select from black, brown, gold, white, blue, or pink for their bear's colors. If a father randomly selects two bear colors, what is the probability that he will select a white bear for his son and a pink bear for his daughter? The father cannot pick the same color for both bears.

Respuesta :

MrRoyal

Answer:

[tex]P(White\ and\ Pink) = \frac{1}{30}[/tex]

Step-by-step explanation:

Given

Colors: Black, Brown, Gold, White, Blue, Pink

Required

P(White and Pink)

Since the father can not select the same color, then it is a selection without replacement.

So, we have:

[tex]P(White\ and\ Pink) = [P(White)\ and\ P(Pink)][/tex]

[tex]P(White\ and\ Pink) = [P(White)\ *\ P(Pink)][/tex]

This gives:

[tex]P(White\ and\ Pink) = [\frac{1}{6}\ *\frac{1}{6-1}][/tex]

[tex]P(White\ and\ Pink) = [\frac{1}{6}\ *\frac{1}{5}][/tex]

[tex]P(White\ and\ Pink) = [\frac{1}{30}][/tex]

[tex]P(White\ and\ Pink) = \frac{1}{30}[/tex]

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