Respuesta :

Answer:

[tex]f^{-1}[/tex](x)=2x+10

Step-by-step explanation:

f(x)=[tex]\frac{x}{2}[/tex]-5

Let y= [tex]\frac{x}{2}[/tex]-5

y= [tex]\frac{y}{2}[/tex]-5

x+5= [tex]\frac{y}{2}[/tex]

Both side multiple 2,

2x+10=y

[tex]f^{-1}[/tex](x)=2x+10