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4. Two dice are thrown together; find the probability of getting (i)
doublet(shows same number on both die .eg (4,4) (2,2)
(ii) sum on both the dice is 7. (iii). Prime number on both the dice. (iv)
both are odd numbers (v). First die shows odd (vi). Sum greater than 10.​

Respuesta :

Answer:

Step-by-step explanation:

favorable outcomes=11,22,33,44,55,66.

P=6/36=1/6

(ii) favorable outcomes=16,25,34,43,52,61

P=6/36=1/6

(iii)

favorable outcomes=

11,13,15,

31,33,35,

51,53,55

P=9/36=1/4

(iv)

favorable outcomes=

11,12,13,15,

21,22,23,25,

31,32,33,35,

51,52,53,55

P=16/36=4/9

(v)

favorable events=

11,12,13,14,15,16,

31,32,33,34,35,36,

51,52,53,54,55,56

P=18/36=1/2

(vi)

favorable events=55

P=1/36

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