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In the addition reaction of HI to 2-methyl-2-butene, the Markovnikov addition mechanism involves: Group of answer choices attack of 2-methyl-2-butene initiated by an iodine atom. formation of a carbocation at carbon two (C-2). isomerization of 2-iodo-2-methylbutene. formation of carbocation at carbon three (C-3). attack of 2-methyl-2-butene initiated by an iodide ion

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Answer:

formation of a carbocation at carbon two (C-2)

Explanation:

Markovnikov  rule states that; "When a protic acid HX (X = Cl, Br, I) is added to an asymmetrically substituted alkene, addition of acidic hydrogen takes place at the less substituted carbon atom of the double bond, while halide X is added to the more alkyl substituted carbon atom" (Chemistry Learner).

Hence, in the addition of HI, H is first added to the C-3(less substituted carbon atom of the double bond). This creates a  tertiary carbocation at C-2 which is more stable. Addition of the iodide ion subsequently leads to a Markovnikov  product.

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