6) Four bacteria are placed in a petri dish. The population will double every day. The formula for the
number of bacteria in the dish on day tis
N(t) = 4(2)^t
where t is the number of days after the four bacteria are placed in the dish. How many bacteria are
in the dish five days after the four bacteria are placed in the dish?

Respuesta :

Answer:

128

Step-by-step explanation:

N(t) = 4(2)^t

N(t) = 4(2)^5

N(t) = 4(32)

N(t) = 128

The number of bacteria that are

in the dish five days after the four bacteria are placed in the dish is; 128 bacteria

We are given the formula for the

number of bacteria in the dish on day as;

N(t) = 4(2)^t

Where t is number of days after the four bacteria are placed in the dish.

Now we are told tof find the number of bacteria in the dish after 5 days.

Thus, we would put 5 for t in the given equation to get;

N(5) = 4(2)^5

N(5) = 4(32)

N(5) = 128

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