Given:
The graph of a trend line.
To find:
The equation of the trend line is slope intercept form.
Solution:
From the given graph it is clear that the equation of the trend line is passes through the points (0,25) and (5,50).
Slope of the line is:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\dfrac{50-25}{5-0}[/tex]
[tex]m=\dfrac{25}{5}[/tex]
[tex]m=5[/tex]
The line passes through the point (0,25). So, the y-intercept of the line is 25.
Slope intercept form of a line is:
[tex]y=mx+b[/tex]
Where, m is slope and b is y-intercept.
The slope intercept from of the line is:
[tex]y=(5)x+(25)[/tex]
[tex]y=5x+25[/tex]
Therefore, the equation for the trend line in slope -intercept form is [tex]y=5x+25[/tex].
