Respuesta :
Answer:
Volume of gasoline overflow(v)= 40/9 L (I.e. 4.44 L)
Explanation:
Use v1/T1=v2/T2
.....overflow(V)=v2-v1
Note; Take temperature in absolute scale or kelvin scale
The overflow volume of the gas is required.
The overflow volume is 4.44 L.
[tex]V_1[/tex] = Initial volume = 64 L
[tex]T_1[/tex] = Initial temperature = [tex]15+273.15=288.15\ \text{K}[/tex]
[tex]V_2[/tex] = Final volume
[tex]T_2[/tex] = Final temperature = [tex]35+273.15=308.15\ \text{K}[/tex]
From the gas laws we have the relation
[tex]\dfrac{V_2}{V_1}=\dfrac{T_2}{T_1}\\\Rightarrow V_2=\dfrac{T_2}{T_1}V_1\\\Rightarrow V_2=\dfrac{308.15}{288.15}\times 64\\\Rightarrow V_2=68.44\ \text{L}[/tex]
Overflow volume
[tex]\Delta V=V_2-V_1=68.44-64\\\Rightarrow \Delta V=4.44\ \text{L}[/tex]
Learn more:
https://brainly.com/question/22811432?referrer=searchResults