Answer:
8900 J
Explanation:
Let heat absorbed be Q1 and heat rejected be Q2.
Q1 = 1000 J, efficiency η = 11% = 0.11
Then, Efficiency of engine can be found be using the following formula,
[tex]\eta = \frac{Q_1-Q_2}{Q_1}[/tex]
⇒ [tex]0.11 = \frac{10000-Q_2}{10000}\\Q_2 = 10000- 1100= 8900 J[/tex]
Therefore, energy does it expels to the environment per cycle = 8900 J