roe29
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PLZ HELP!!
Create the equation of a quadratic polynomial, in standard form, that has zeroes of -5 and 2 and which passes through the point (3,-24). ​

Respuesta :

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Answer:

  y = -3x^2 -9x +30

Step-by-step explanation:

When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...

  f(x) = (x +5)(x -2)

At the point x=3, the value of this product is ...

  f(3) = (3 +5)(3 -2) = (8)(1) = 8

In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...

  y = -3(x +5)(x -2)

  y = -3x^2 -9x +30 . . . . . standard form

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