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A train leaves Miami at 4:00 PM. A second train leaves the same city in the same direction at 8:00 PM. The second train travels 124mph faster than the first. If the second train overtakes the first at 10:00 PM, what is the speed of each of the two trains?

Respuesta :

ishikavajpai

Answer:

Step-by-step explanation:

The late but fast train traveled for 2 hours while the slow but early train traveled for 6 hours.

              SPEED       TIME     DISTANCE

SLOW EARLY       r           6          d

FAST LATE      r+124         2          d

Catchup means each train traveled equal distance
Distance = speed x time
If we call the slower speed S we can make this equation...
6 x S = 2 x F = 2 x (S + 124)
6S = 2S + 248
4S = 248
S = 62
So the slow train is travelling at 62mph and the fast train at 186mph