Answer:
44.2 L
Explanation:
Use Charles Law:
[tex]\frac{V1}{T1} =\frac{V2}{T2}[/tex]
We have all the values except for V₂; this is what we're solving for. Input the values:
[tex]\frac{56 L}{346K} =\frac{V2}{273K}[/tex] - make sure that your temperature is in Kelvin
From here, we need to get V₂ by itself. To do this, multiply by 273 on both sides:
[tex]\frac{56*273}{346} = V2[/tex]
Therefore, V₂ = 44.2 L
It's also helpful to know that temperature and volume are linearly related. So, when temperature drops, so will volume and vice versa.
