Which two changes would make this reaction product-favored? 3H2 + N2 ⇄ 2NH3 + energy  A. Decreasing the pressure  B. Increasing the temperature  C. Increasing the pressure  D. Reducing the temperature

Respuesta :

Answer:C and D

Explanation:Just did it

Increasing the pressure and Decreasing the temperature are the two changes would make this reaction product-favored.

What is Equilibrium ?

It is a state when a reaction is reversible and both forward and reverse reaction occur simultaneously at the same rate .

In the process of manufacture of Ammonia , both forward and reverse reaction are taking place

N₂(g) + 3H₂ (g) →  2NH₃ (g)

2NH₃(g)  →  N₂ (g) + 3H₂ (g)

when these reaction occur at same rate , the state is called equilibrium and is represented by

N₂ (g) + 3H₂(g) ⇔ 2NH₃(g) +Heat

As we can see from the equation , heat is produced in the forward reaction so if we increase the temperature the reverse reaction will be favored ,

On decreasing temperature the reaction will become product favored .

While on increasing the Pressure the manufacture of Ammonia increases.

Therefore Option C and Option D are the two changes would make this reaction product-favored.

To know more about Equilibrium

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