write the slope-intercept form of the equation of the line trough the given point with the given slope.
trough : (1, -4), slope= -8
A.y=8x+4
B.y=-8x+4
C.y=4x+8
D.y=3x+8

write the slopeintercept form of the equation of the line trough the given point with the given slope trough 1 4 slope 8 Ay8x4 By8x4 Cy4x8 Dy3x8 class=

Respuesta :

Given:

Point = (1,-4), Slope - 8

Point = (1,5), Slope =1

To find:

The slope-intercept forms of the given lines.

Solution:

The slope intercept form of a line is:

[tex]y=mx+b[/tex]

The point slope form is:

[tex]y-y_1=m(x-x_1)[/tex]

where, m is the slope of the line.

We have, Point = (1,-4), Slope - 8. So, the equation of the line is:

[tex]y-(-4)=-8(x-1)[/tex]

[tex]y+4=-8x+8[/tex]

[tex]y=-8x+8-4[/tex]

[tex]y=-8x+4[/tex]

Therefore, the correct option is B.

We have, Point = (1,5), Slope =1. So, the equation of the line is:

[tex]y-5=1(x-1)[/tex]

[tex]y-5=x-1[/tex]

[tex]y=x-1+5[/tex]

[tex]y=x+4[/tex]

Therefore, the correct option is D.