Answer:
A point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
Explanation:
We can find the distance with the following equation since the acceleration is cero (the disk rotates at a constant rate):
[tex] d = v*t [/tex]
Where:
v: is the tangential speed of the disk
t: is the time = 30 s
The tangential speed can be found as follows:
[tex] v = \omega*r [/tex]
Where:
ω: is the angular speed = 100 rpm
r: is the radius = 50 cm = 0.50 m
[tex] v = \omega*r = 100 \frac{rev}{min}*\frac{2\pi rad}{1 rev}*\frac{1 min}{60 s}*0.50 m = 5.24 m/s [/tex]
Now, the distance traveled by the disk is:
[tex] d = v*t = 5.24 m/s*30 s = 157.2 m [/tex]
Therefore, a point on the outside rim will travel 157.2 meters during 30 seconds of rotation.
I hope it helps you!
