Someone please help me! I need this In standard form

Answer: [tex]x^{2} +y^{2}=16[/tex]
Step-by-step explanation:
Standard form for a circle is
[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex] where (h,k) is the center
[tex](x-0)^{2} +(y-0)^{2} = 4^{2} \\x^{2} +y^{2}=16[/tex]