Respuesta :
Let us first resolve the given numbers into prime factors.
By prime factorization,
[tex] \longmapsto [/tex] √8 = √( 2 × 2 × 2)
[tex] \longmapsto [/tex] √8 = 2√2
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
[tex] \longmapsto [/tex] √98 = √( 2 × 7 × 7)
[tex] \longmapsto [/tex] √98 = 7√2
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
[tex] \longmapsto [/tex] √32 = √( 2 × 2 × 2 × 2 × 2)
[tex] \longmapsto [/tex] √32 = 2 × 2√2
[tex] \longmapsto [/tex] √32 = 4√2
According to the question,
[tex] \longmapsto [/tex] √8+√98+√32
[tex] \longmapsto [/tex] 2√2 + 7√2 + 4√2
- Taking √2 as common.
[tex] \longmapsto [/tex] √2(2 + 7 + 4)
[tex] \longmapsto [/tex] √2(13)
[tex] \longmapsto [/tex] 13√2
So, we get that :