Answer:
r = 0.05 m = 5 cm
Explanation:
Applying ampere's law to the wire, we get:
[tex]B = \frac{\mu_oI}{2\pi r}\\\\r = \frac{\mu_oI}{2\pi B}[/tex]
where,
r = distance of point P from wire = ?
μ₀ = permeability of free space = 4π x 10⁻⁷ N/A²
I = current = 2 A
B = Magnetic Field = 8 μT = 8 x 10⁻⁶ T
Therefore,
[tex]r = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(2\ A)}{2\pi(8\ x\ 10^{-6}\ T)}\\\\[/tex]
r = 0.05 m = 5 cm
