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The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1741 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 18.68 mL of the 0.1741-M Ce4+ solution is required to react completely with 30.00 mL of the H3AsO3 solution.
Calculate the concentration of the H3AsO3 solution.

Respuesta :

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Answer:

0.0542 M

Explanation:

Let;

CA = concentration of Ce4+ solution = 0.1741 M

VA = volume of Ce4+ solution = 18.68 mL

CB = concentration of H3AsO3 = ?

VB  = volume of H3AsO3 = 30.00 mL

NA = Number of moles of Ce4+ solution = 2

NB = Number of moles of H3AsO3  = 1

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.1741 * 18.68 * 1/30.00 * 2

CB = 0.0542 M

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