Answer:
A) chlorine
Explanation:
To solve this question we can use:
PV = nRT
In order to solve the moles of the gas. With the moles and the mass we can find the molar mass of the gas to have an idea of its identy:
PV = nRT
PV / RT = n
Where P is pressure: 603mmHg * (1atm / 760mmHg) = 0.7934atm
V = 100mL = 0.100L
R is gas constant = 0.082atmL/molK
T is absolute temperature = 14°C + 273.15 = 287.15K
0.7934atm*0.100L / 0.082atmL/molK*287.15K = n
3.37x10⁻³ moles of the gas
In 0.239g. The molar mass is:
0.239g / 3.37x10⁻³ moles = 70.9g/mol
The gas with this molar mass is Chlorine, Cl₂:
