hey!! can someone please help me with these math problems? I would appreciate it, thank you(:
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{x=-1/3-10/3y
5x+20y=5
5(-1/3-10/3y)+20y=5
solve the equation
.
.
Y=5
substitute the value of y into the equation
x=-1/3-10/3×2
.solve the equation
.
.x=-7
(x,y)=(-7,2)
{3×(-7)+10×2=-1
5x(-7)+28×2=5
simplify
{-1=-1
5=5
the ordered pair is asolution
(X,Y)=(-7,2)
That's all!!!!
Answer:
x = -7 y = 2
Step-by-step explanation:
Let's solve this using the elimination method:
3x + 10y = -1. #1
5x + 20y = 5. #2
Multiply Eqtn #1 by -2
-6x - 20y = 2
5x + 20y = 5
Add these two equations together and we will get
-x = 7 or x = -7
Use this value of x into either Eqtn #1 or #2
3(-7) + 10y = -1 ----> 10y = 20 or y = 2