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A circular pool has a footpath around the circumference. The equation x2 + y2 = 2,500, with units in feet, models the
outside edge of the pool. The equation x2 + y2 = 3,422.25, with units in feet, models the outside edge of the footpath.
What is the width of the footpath?
8.5 ft
17 ft
O 30 ft
O 58.5 ft

Respuesta :

Answer:A. 8.5 ft

Step-by-step explanation:

edge2021

The width of the footpath is 8.5 feet.

What is radius in a circle?

Radius of a circle is the distance from the center of the circle to any point on it's circumference.

given equation is :x² + y² = (r)²

We have for the pool:

x²  +  y²  = 2500      or   x²  +  y²  = (50)²

So, for the outside edge of the footpath

x²  +  y²  = 3422.25  or x² + y²  = (58.5)²

So, we find the radius of each circumference

  • For the outside edge of the pool

r₁  = 50 feet

  • For the outside edge of the footpath

r₂ = 58,5  feet

  • Then the width of the footpath is  

58,5  - 50  =  8,5 feet

Thus, width of the footpath is 8.5 feet.

Learn more about this concept here:

https://brainly.com/question/23454458

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