Answer:
The area of the rhombus is 25.83 cm².
Step-by-step explanation:
The area of a rhombus is given by:
[tex] A = \frac{d_{1} \times d_{2}}{2} [/tex]
Where:
d₁: is one diagonal
d₂: is the other diagonal = d₁ + 4 cm
We know that one side length of the rhombus is equal to d₁. We can imagine a right triangle inside the rhombus, with the following dimensions:
h: hypotenuse of the right triangle
a: one side of the right triangle
b: is the other side of the right triangle
From the above we know that:
h = d₁
[tex] a = \frac{d_{2}}{2} = \frac{d_{1} + 4}{2} [/tex]
[tex] b = \frac{d_{1}}{2} [/tex]
We can find d₁ with Pitagoras:
[tex] h^{2} = a^{2} + b^{2} [/tex]
[tex] d_{1}^{2} = (\frac{d_{1} + 4}{2})^{2} + (\frac{d_{1}}{2})^{2} [/tex]
[tex] d_{1}^{2} = \frac{1}{4}(d_{1}^{2} + 8d_{1} + 16 + d_{1}^{2}) [/tex]
By solving the above quadratic equation for d₁ and taking the positive solution we have:
[tex] d_{1} = 5.46 cm [/tex]
So, d₂ is:
[tex] d_{2} = d_{1} + 4 = 5.46 cm + 4 cm = 9.46 cm [/tex]
Now, we can find the area:
[tex] A = \frac{d_{1} \times d_{2}}{2} = \frac{5.46 cm \times 9.46 cm}{2} = 25.83 cm^{2} [/tex]
Therefore, the area of the rhombus is 25.83 cm².
I hope it helps you!
