Answer: [tex]y=2x-11[/tex]
Step-by-step explanation:
Given
The line has a slope of 2 and passes through (3,-5)
Using slope point form that is
[tex]\Rightarrow \dfrac{y-y_1}{x-x_1}=m[/tex]
Insert values
[tex]\Rightarrow \dfrac{y-(-5)}{x-3}=2\\\\\Rightarrow y+5=2x-6\\\Rightarrow y=2x-11\ or\ 2x-y=11[/tex]
