Respuesta :
Answer:
Whereby circle [tex]\bigodot[/tex]P can be obtained from circle [tex]\bigodot[/tex]O by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, [tex]\bigodot[/tex]O is similar to [tex]\bigodot[/tex]P
Step-by-step explanation:
The given center of the circle [tex]\bigodot[/tex]O = (-2, 7)
The radius of [tex]\bigodot[/tex]O, r₁ = 5
The given center of the circle [tex]\bigodot[/tex]P = (12, -1)
The radius of [tex]\bigodot[/tex]P, r₂ = 12
The similarity transformation to prove that [tex]\bigodot[/tex]O and [tex]\bigodot[/tex]P are similar are;
a) Move circle [tex]\bigodot[/tex]O 14 units to the right and 8 units down to the point (12, -1)
b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4
Therefore, the radius of circle [tex]\bigodot[/tex]O is increased by 2.4
We then obtain [tex]\bigodot[/tex]O' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle [tex]\bigodot[/tex]P
∴ Circle [tex]\bigodot[/tex]P can be obtained from circle [tex]\bigodot[/tex]O by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, [tex]\bigodot[/tex]O is similar to [tex]\bigodot[/tex]P.
