Which point is a solution to the system of inequalities?

StartLayout Enlarged left-brace first row y greater-than-or-equal-to one-half x squared + 4 second row y less-than StartRoot x + 2 EndRoot + 6 EndLayout

(–2, 6)
(1, 9)
(2, 8)
(0, 4)

Respuesta :

D) (0,4)

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The correct option is 4. (0,4)

Given inequalities are [tex]y\geq \frac{1}{2} x^{2} +4[/tex] and [tex]y< \sqrt{x+2}+6[/tex] .

Taking first inequality,

[tex]y\geq \frac{1}{2} x^{2} +4[/tex]

Or, [tex]y=\frac{1}{2} x^{2} +4[/tex]

now checking which option satisfy the above equation.

Taking option 1.(–2, 6)

on putting x= - 2 and y=6, we get

[tex]6= \frac{1}{2} (-2)^2+4[/tex]

[tex]6=6[/tex]

Hence option 1 (–2, 6) satisfy the equation.

Similarly checking for option 2 and 3 we find that these options totally not follow inequality, so option 3 and option 2 must not be the solution of given inequality.

Now option 4 (0, 4).

Putting x=0 and y = 4, we get

[tex]4=0+4\\4=4[/tex]

Hence option 4 also satisfy the first inequality.

Now we have two option to choose our final answer option 1 and option 4.

since option 4 lies in the shaded region so option 4 will be correct option.

Hence the correct option is 4. (0,4)

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