Answer:
[tex]6x + 6[/tex]
Step-by-step explanation:
Given
[tex]6 (-\frac{1}{2}x + 2) + \frac{1}{2} (18x-12)[/tex]
Required
Express as [tex]ax + b[/tex]
We have:
[tex]6 (-\frac{1}{2}x + 2) + \frac{1}{2} (18x-12)[/tex]
Open brackets
[tex]6 (-\frac{1}{2}x + 2) + \frac{1}{2} (18x-12) = 6 *-\frac{1}{2}x + 6*2 + \frac{1}{2} *18x-\frac{1}{2} *12[/tex]
Evaluate all multiplications
[tex]6 (-\frac{1}{2}x + 2) + \frac{1}{2} (18x-12) = -3x + 12 + 9x-6[/tex]
Collect like terms
[tex]6 (-\frac{1}{2}x + 2) + \frac{1}{2} (18x-12) = 9x-3x + 12-6[/tex]
[tex]6 (-\frac{1}{2}x + 2) + \frac{1}{2} (18x-12) = 6x +6[/tex]
Hence, the expression in form of [tex]ax + b[/tex] is [tex]6x + 6[/tex]
