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7. A box contains 10 black, 12 white, and 18 red balls. One ball is drawn at
random and replaced. (a) Find the theoretical probability that the ball
drawn is black. (b) Balls are chosen and replaced 40 times. Look at the
table below, find the experimental probability that the ball drawn is black.
(c) Compare the experimental probability of the black ball drawn to its
theoretical probability.
Table:
Color. Times picked
black. 15
white. 12
red. 13

Respuesta :

kyronwitter5678

Answer:

1. 10/40 = 1/4

1b. 15/40 = 3/8

1c. 10/40 = 1/4 and 15/40 = 3/8

Step-by-step explanation:

1. So since there are 40 balls (18 + 12 + 10) and 10 of those balls are black the theoretical probability would just be 10 over 40, ([tex]\frac{10}{40}[/tex]).

1b. On the table there are 15 black balls so that would be, [tex]\frac{15}{40}[/tex].

1c. The theoretical probability is 1/4 and the experimental probability is 3/8.

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