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Two similar shapes have a pair of corresponding sides which are easily measurable.
The smaller shape's side has a length of 4m, and the larger shape has a side length of
5m. If the area of the smaller shape is 80m², what is the area of the larger shape?

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Answer:

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Step-by-step explanation:

Answer:

125 m²

Step-by-step explanation:

Given sides of similar shapes in the ratio a : b then

ratio of area = a² : b²

Here ratio of sides = 4 : 5 , so

ratio of areas = 4² : 5² = 16 : 25

let x be the area of the larger shape then by proportion

[tex]\frac{16}{80}[/tex] = [tex]\frac{25}{x}[/tex] ( cross- multiply )

16x = 2000 ( divide both sides by 16 )

x = 125

Then area of larger shape is 125 m²