Answer: The volume of nitrogen gas at STP is 44.8 L.
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation for it follows:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ...(1)
We are given:
Given mass of [tex]NaN_3[/tex] = 130.0 g
Molar mass of [tex]NaN_3[/tex] = 65.01 g/mol
Using equation 1:
[tex]Moles of NaN_3=\frac{130.0 g}{65.01g/mol}=2mol[/tex]
For the given chemical equation:
[tex]2NaN_3(s) \rightarrow 2Na(s) + 3N_2(g)[/tex]
By the stoichiometry of the reaction:
2 moles of [tex]NaN_3[/tex] produces 3 moles of nitrogen gas
At STP:
1 mole of a gas occupies 22.4 L of volume
So, 2 moles of nitrogen gas will occupy [tex]=\frac{22.4L}{1mol}\times 2mol=44.8L[/tex] of volume
Hence, the volume of nitrogen gas at STP is 44.8 L.
