Respuesta :
Answer:
The final concentration of the Randyne in grams per milliliter = 0.011 g/mL
Explanation:
As we know
C1V1 = C2V2
C1 and C2 = concentration of solution 1 and 2 respectively
V1 and V2 = Volume of solution 1 and 2 respectively
Substituting the given values, we get -
[tex]50 * 15 = X * (15+50)\\X = 11.54[/tex] mg/mL
The final concentration of the Randyne in grams per milliliter = 0.011 g/mL
The final concentration of the Randyne in this solution is 0.01 g /mL.
How to calculate dilutions?
It is very important to know the dilution methods in a chemistry lab. The dilution from the stock solution can be prepared by using the formula,
[tex]C_1V_1 = C_2V_2[/tex]
Where,
[tex]C_1[/tex]- concentration of the stock solution
[tex]V_1[/tex] - the volume of the stock solution
[tex]C_2[/tex] - concentration of the diluted solution
[tex]V_2[/tex] - the volume of diluted solution
Put the values in the formula,
[tex]50 \times 15 = C_2 \times 75 \\\\C_2 = \dfrac {750}{75 }\\\\C_2 = 10{\rm \ mg/mL \ \ \ or} \\\\ C_2 = 0.01 \rm \ g/mL[/tex]
Therefore, the final concentration of the Randyne in this solution is 0.01 g /mL.
Learn more about dilution methods:
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