Respuesta :

altavistard

Answer:

181 mi^2

Step-by-step explanation:

Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;

Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.

Dimensions of circle:  r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.

Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2

bowmaian000

Answer:

Step-by-step explanation:

So first off. lets take chunks of this shape. We have a 6x8 rectangle, a 4x5 rectangle, and a 1/4 circle with a radius of 12.

The area of a rectnagle is just length x width.

So lets plug in our values for our two ractnagles, and see what we get:

6*8

=

48

So our first rectangle has a area of 48

Next we have:

4*5

=

20

So our second rectangle has an area of 20.

Add these otgether you get 68.

Finally we have our 1/4 circle. To solve this, find the area of the full circle and divide by 4.

We already know the radius, which is 12, and the formula for area of a circle is:

a=πr^2

Plug in 12:

a=π12^2

=

a=π144

dividing by four for the 1/4circle:

a=π36

So this means your answer is either:

68 +36π

Or:

181.097(solving pi*36)

Either of these work, if the problem allows pi, then use the first one, If not, use the bottom one.

Hope this helps!

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