Answer:
See explanation below
Explanation:
a) First, as the KCl is a salt, this will ve completely dissociated by water in solution and the reaction taking place would be:
KCl <-----------> K⁺ + Cl⁻
b) According to the above reaction, the Ksp or constant of solubility product will be just the concentration of the products. This is because solid compounds do not contribute in the equilibrium expression, cause they have a constant concentration near to 1. Same thing happens with liquid compounds. So, based on this the Ksp expression for the above reaction is:
KCl(s) <-----------> K⁺(aq) + Cl⁻(aq)
Ksp = [K⁺] [Cl⁻]
c) To find this solubility we need to write the Ksp expression from above, use the given Ksp value and then solve for the solubility:
KCl(s) <-----------> K⁺(aq) + Cl⁻(aq)
Ksp = [K⁺] [Cl⁻]
21.7 = s * s
21.7 = s²
s = 4.66 mol/L
d) To know this, we need to see the concentration of the KCl in solution with the given data of 21.5 moles and the 5 liters of solution:
[K⁺] = [Cl⁻] = 21.5 / 5 = 4.3 mol/L
If we want to calculate the Ksp at this conditions we have:
Ksp2 = (4.3)²
Ksp2 = 18.49
As this value is lower than the actual Ksp value, we can conclude that this solution is undersaturated.
Hope this helps