Answer:
The answer is "0.9192".
Step-by-step explanation:
[tex]\mu=109\\\\\sigma=10\\\\n=25\\\\\to P(\bar{x}< 111.8)=P(\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}} < \frac{111.8-109}{\frac{10}{\sqrt{25}}})\\\\[/tex]
[tex]=P(2<1.4)\\\\=\phi (1.4)\\\\=0.9192[/tex]