Answer:
37) ±√29 - 4
Completing the square utilizes this formula [tex](\frac{b}{2})^{2}[/tex]. We know that b=8, 8 can be plugged into this formula to get [tex](\frac{8}{2})^2[/tex]. Simplify to get 16. Now, we can add this into the equation to get [tex]k^{2}+8k+13=26[/tex]. Subtract 26 to both sides, so the equation can equal to 0. [tex]k^{2} +8k-13=0[/tex] would be the resulting equation. Now, let's use quadratic formula to find the solution. The quadratic formula is (-b+-√b^2-4ac) / 2a. Plug in all of our values to get (-8+-√8^2-4(1)(-13)/2(1). Simplify the equation to get ±√29 - 4.
38) ±√21 - 2
Let's use the same formula. b=4, so [tex](\frac{4}{2} )^2[/tex]. Simplify to get 4. Add that into the equation to get [tex]x^{2}+4x-5=12[/tex]. Subtract 8 on both sides, so the equation can equal to 0. [tex]x^{2}+4x-17=0[/tex] would be the result. Use the quadratic formula again to find the solution. Plug in all of the values to get ±√21 - 2
If you're confused on any part of the explanation, feel free to ask :)
