Answer:
Over 300 students did not support start time after 8:00am
Step-by-step explanation:
Given
[tex]N = 600[/tex] --- population
[tex]n = 40[/tex] --- sample
See attachment for dataset
Required [True/False]
Over 300 wants start time after 8:00am
First, we calculate the number of samples that wants start time after 8:00am
[tex]x = 8:30am\ start + 9:00am\ start[/tex]
For sample 1
[tex]x_1 = 18[/tex]
The corresponding value of x1 in the overall population is:
[tex]X_1 = \frac{x_1}{n} * N[/tex]
[tex]X_1 = \frac{18}{40} * 600[/tex]
[tex]X_1 = \frac{18 * 600}{40}[/tex]
[tex]X_1 = \frac{10800}{40}[/tex]
[tex]X_1 = 270[/tex]
For sample 2
[tex]x_2 = 19[/tex]
The corresponding value of x2 in the overall population is:
[tex]X_2 = \frac{x_2}{n} * N[/tex]
[tex]X_2 = \frac{19}{40} * 600[/tex]
[tex]X_2 = \frac{19* 600}{40}[/tex]
[tex]X_2 = \frac{11400}{40}[/tex]
[tex]X_2 = 285[/tex]
None of X1 and X2 is greater than 300.
Hence, over 300 students did not support start time after 8:00am
None of X1 and X2 is greater than 300. so, over 300 students did not support start time after 8:00 am.
The population is 600 and the sample is 40.
The population of inference refers to the population (or universe) to which the results from a sample survey are meant to generalize.
Over 300 students did not support start time after 8:00 am
For sample 1
[tex]\rm x_{1} =18\\[/tex]
The corresponding value of x1 in the overall population is:
[tex]\rm X_{1} =\frac{x_{1} }{n} \times N\\\rm X_{1} =\frac{18}{40} \times 600\\\rm X_{1} =\frac{10800}{40}\\ \rm X_{1} =270\\[/tex]
For sample 2
[tex]\rm x_{2} =19[/tex]
The corresponding value of x2 in the overall population is:
[tex]\rm X_{2} =\frac{x_{2} }{n} \times N\\\rm X_{2} =\frac{19}{40} \times 600\\\rm X_{2} =\frac{11400}{40}\\ \rm X_{2} =285\\[/tex]
None of X1 and X2 is greater than 300.
Hence, over 300 students did not support start time after 8:00 am.
Learn more about the population of inference here:
https://brainly.com/question/3640262
