Answer:
4) 1400 [tex]in^3[/tex]
5) 304[tex]\Pi[/tex] or 954.56[tex]yd^3[/tex]
6) 315 [tex]ft^2[/tex]
Step-by-step explanation:
[tex]4)[/tex]
[tex]V = \frac{lwh}{3} = \frac{20*20*10.5}{3} = \frac{4200}{3} = 1400[/tex]
[tex]5)[/tex]
[tex]A = \Pi(\frac{D}{2})^2 = \Pi(\frac{8}{2})^2 = \Pi*4^2 = 16\Pi[/tex]
[tex]V = A * h = 16\Pi * 19 = 304\Pi = 304 * 3.14 = 954.56[/tex]
[tex]6)[/tex]
[tex]h^2 = 8^2 + 8^2 => h^2 = 64 + 64 = 128 => h =\sqrt{128}[/tex]
[tex]A_1 = 2(\frac{8*\sqrt{128}}{2}) = 8*\sqrt{128} = 32 = 90.5[/tex]
[tex]A_2 = 2(14 * 8) = 2*112 = 224[/tex]
[tex]A = A_1 + A_2 = 91 + 224 = 315[/tex]
