Answer:
The answer is "0.1040"
Step-by-step explanation:
Margin of error[tex]=Z_{\frac{\alpha}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\[/tex]
[tex]=Z_{\frac{0.10}{2}} \sqrt{\frac{\frac{36}{60}(1-\frac{36}{60})}{60}}\\\\=1.645 \times 0.0632\\\\=0.1040\\\\[/tex]