Answer:
The right answer is "50.48°F".
Explanation:
The given values are:
Temperature at 3000 feet,
= 72°F
Temperature change for 1000 feet,
= 5.38°F
Normal lapse rate,
= [tex]\frac{5.38^{\circ}F}{1000 \ feet}[/tex]
Change in elevation will be:
= [tex]7000-3000[/tex]
= [tex]4000 \ feet[/tex]
hence,
The temperature change for 4000 feet will be:
= [tex]5.38\times 4[/tex]
= [tex]21.52^{\circ}F[/tex]
The temperature change for 7000 feet will be:
= [tex]72-21.52[/tex]
= [tex]50.48^{\circ}F[/tex]
