Answer:
Solution given:
Cos -θ:[tex]\frac{\sqrt{3}}{4}[/tex]
since cos -θ=Cos θ
Cos θ :[tex] \frac{\sqrt{3}}{4} [/tex]
[tex]\frac{\sqrt{b}}{h} [/tex]=:[tex] \frac{\sqrt{3}}{4} [/tex]
b=[tex]\sqrt{3} [/tex]
h=4
p=[tex] \sqrt{4²-(\sqrt{3})²} [/tex]=[tex] \sqrt{13}[/tex]
So
Sin θ=[tex]\frac{p}{h} [/tex]=[tex]\frac{\sqrt{13}}{4} [/tex]
So third one is a required answer.
