Answer:
1.
For triangle 1
[tex]a = 3\sqrt{5}[/tex]
For triangle 2
[tex]x = 2\sqrt{2}[/tex]
2.
Way 1
By reducing the length of the side 4 to 3.60
Way 2
By increasing the length of side 7 to 7.21
Step-by-step explanation:
The complete question is attached in the image
Solution
1.
Both the triangles are right angled triangle
For triangle 1
[tex]7^2 = 2^2 + a^2\\49 = 4 + a^2\\a^2 = 45\\a = 3\sqrt{5}[/tex]
For triangle 2
[tex]4^2 = x^2+x^2\\2x^2 = 4*4\\x^2 = 8\\x = 2\sqrt{2}[/tex]
2.
Way 1
By reducing the length of the side 4 to 3.60
Way 2
By increasing the length of side 7 to 7.21