Respuesta :

msm555

Answer:

solution given:

Area of triangle ABC=½b×h=½×18×21=189km²

Area of square DEFG=l²=9²=81km²

Area of rectangle DHIJ=l×b=4×13=52km²

Total area =189+81+52=322 square kilometers.

Ver imagen msm555
Nayefx

Answer:

[tex] \rm\displaystyle A _{ \text{total}} = 322 {km}^{2} [/tex]

Step-by-step explanation:

refer the attachment

we have a triangle,a rectangle and a square

in order to figure out the area of the total figure we need to figure out the area the attached figure first

Triangle:

the triangle has a base of 18 km and a height of 13+6+2=21km

thus,

the area of the triangle is

[tex] \displaystyle \frac{1}{2} \times 18 km\times 21km[/tex]

reduce fraction:

[tex] \displaystyle 9 km\times 21km[/tex]

simplify multiplication:

[tex] \displaystyle 189 km ^{2} [/tex]

Rectangle:

the rectangle has a length of 13km and a width of 4km

thus,

the area of the rectangle is

[tex] \displaystyle 13km \times 4km[/tex]

simplify multiplication:

[tex] \displaystyle {52km}^{2} [/tex]

Square:

the length of every sides of the square is 9km

thus,

the area of the square is

[tex] \displaystyle {(9km)}^{2} [/tex]

simplify square:

[tex] \displaystyle {81km}^{2} [/tex]

Area-total:

[tex] \rm\displaystyle A _{ \text{total}} = A_{ \text{triangle}} + A_{ \text{rectangle}} + A_{ \text{square}}[/tex]

substitute:

[tex] \rm\displaystyle A _{ \text{total}} = 189 {km}^{2} + 52 {km}^{2} + 81 {km}^{2} [/tex]

simplify addition:

[tex] \rm\displaystyle A _{ \text{total}} = 322 {km}^{2} [/tex]

Ver imagen Nayefx